Проблема с кодом.

[scottie]

Program Pr1;
uses crt;
Var B,dT,R,dB,A,Vr1,Vz1,Vr2,Vz2,R1,R2,Z 1,Z2:real;
H:text;
begin
assign(H,'Pr1.txt');
rewrite(H);
dB:=0.001;
B:=0.01;
while B<=0.5 do
begin
Vr1:=0;
Vz1:=1;
A:=9/40;
R:=0.87;
dT:=0.01;
R2:=1;
R1:=1;
Z1:=0;
while R2>=R do
begin
Vr2:=dT*(-B*R1+A*Vr1)+Vr1;
Vz2:=dT*(1-Vz1*A)+Vz1;
R2:=dT*Vr1+R1;
Z2:=dT*Vz1+Z1;
R1:=R2;
Z1:=Z2;
Vr1:=Vr2;
Vz1:=Vz2;
end;
WriteLn(B,Z2);
WriteLn(H,B,Z2);
B:=B+dB;
end;
ReadLn;
close(H);
end.

Program Z(A);
uses crt;
Var A,B,dT,R,dA,Vr1,Vz1,Vr2,Vz2,R1,R2,Z 1,Z2:real;
H:text;
begin
assign(H,'ZA.txt');
rewrite(H);
dA:=9/400;
A:=9/40;
while A<=1.5 do
begin
Vr1:=0;
Vz1:=1;
B:=0.01;
R:=0.87;
dT:=0.01;
R2:=1;
R1:=1;
Z1:=0;
while R2>=R do
begin
Vr2:=dT*(-B*R1+A*Vr1)+Vr1;
Vz2:=dT*(1-Vz1*A)+Vz1;
R2:=dT*Vr1+R1;
Z2:=dT*Vz1+Z1;
R1:=R2;
Z1:=Z2;
Vr1:=Vr2;
Vz1:=Vz2;
end;
WriteLn(A,Z2);
WriteLn(H,A,Z2);
A:=A+dA;
end;
ReadLn;
close(H);
end.

Program Z(R);
uses crt;
Var A,B,dT,R,dA,Vr1,Vz1,Vr2,Vz2,R1,R2,Z 1,Z2:real;
H:text;
begin
assign(H,'ZR.txt');
rewrite(H);
Vr1:=0;
Vz1:=1;
B:=0.01;
A:=9/40;
dT:=0.01;
R2:=1;
R1:=1;
Z1:=0;
while R2>=sqrt(0.3) do
begin
Vr2:=dT*(-B*R1+A*Vr1)+Vr1;
Vz2:=dT*(1-Vz1*A)+Vz1;
R2:=dT*Vr1+R1;
Z2:=dT*Vz1+Z1;
R1:=R2;
Z1:=Z2;
Vr1:=Vr2;
Vz1:=Vz2;
WriteLn(R2,Z2);
WriteLn(H,R2,Z2);
end;
ReadLn;
close(H);
end.


Можно ли эти три программы объединить в одну, чтобы на выходе получалось три отдельных текстовых файла с числовыми значениями для каждого цикла отдельно? Заранее спасибо))

[Google2010]

можно) стучись 553-566-179! недорого!

[ROMA2PVT]

Program Pr1;
uses crt;
Var B,dT,R,dB,A,Vr1,Vz1,Vr2,Vz2,R1,R2,Z1,Z2:real;
H,K,S:text;
begin
assign(H,'C:\Pr1.txt');
rewrite(H);
dB:=0.001;
B:=0.01;
while B<=0.5 do
begin
Vr1:=0;
Vz1:=1;
A:=9/40;
R:=0.87;
dT:=0.01;
R2:=1;
R1:=1;
Z1:=0;
while R2>=R do
begin
Vr2:=dT*(-B*R1+A*Vr1)+Vr1;
Vz2:=dT*(1-Vz1*A)+Vz1;
R2:=dT*Vr1+R1;
Z2:=dT*Vz1+Z1;
R1:=R2;
Z1:=Z2;
Vr1:=Vr2;
Vz1:=Vz2;
end;
WriteLn(B,Z2);
WriteLn(H,B,Z2);
B:=B+dB;
end;
ReadLn;
close(H);
assign(K,'C:\ZA.txt');
rewrite(K);
dB:=9/400;
B:=9/40;
while B<=1.5 do
begin
Vr1:=0;
Vz1:=1;
A:=0.01;
R:=0.87;
dT:=0.01;
R2:=1;
R1:=1;
Z1:=0;
while R2>=R do
begin
Vr2:=dT*(-B*R1+A*Vr1)+Vr1;
Vz2:=dT*(1-Vz1*A)+Vz1;
R2:=dT*Vr1+R1;
Z2:=dT*Vz1+Z1;
R1:=R2;
Z1:=Z2;
Vr1:=Vr2;
Vz1:=Vz2;
end;
WriteLn(B,Z2);
WriteLn(K,B,Z2);
B:=B+dB;
end;
ReadLn;
close(K);
assign(S,'C:\ZR.txt');
rewrite(S);
Vr1:=0;
Vz1:=1;
B:=0.01;
A:=9/40;
dT:=0.01;
R2:=1;
R1:=1;
Z1:=0;
while R2>=sqrt(0.3) do
begin
Vr2:=dT*(-B*R1+A*Vr1)+Vr1;
Vz2:=dT*(1-Vz1*A)+Vz1;
R2:=dT*Vr1+R1;
Z2:=dT*Vz1+Z1;
R1:=R2;
Z1:=Z2;
Vr1:=Vr2;
Vz1:=Vz2;
WriteLn(R2,Z2);
WriteLn(S,R2,Z2);
end;
ReadLn;
close(S);
end.

Так?

[ROMA2PVT]

Program Pr1;
uses crt;
Var B,dT,R,dB,A,dA,Vr1,Vz1,Vr2,Vz2,R1,R2,Z1,Z2:real;
H,K,S:text;
begin
assign(H,'C:\Pr2.txt');
rewrite(H);
dB:=0.001;
B:=0.01;
while B<=0.5 do
begin
Vr1:=0;
Vz1:=1;
A:=9/40;
R:=0.87;
dT:=0.01;
R2:=1;
R1:=1;
Z1:=0;
while R2>=R do
begin
Vr2:=dT*(-B*R1+A*Vr1)+Vr1;
Vz2:=dT*(1-Vz1*A)+Vz1;
R2:=dT*Vr1+R1;
Z2:=dT*Vz1+Z1;
R1:=R2;
Z1:=Z2;
Vr1:=Vr2;
Vz1:=Vz2;
end;
WriteLn(B,Z2);
WriteLn(H,B,Z2);
B:=B+dB;
end;
ReadLn;
close(H);
assign(K,'C:\Z2.txt');
rewrite(K);
dA:=9/400;
A:=9/40;
while A<=1.5 do
begin
Vr1:=0;
Vz1:=1;
B:=0.01;
R:=0.87;
dT:=0.01;
R2:=1;
R1:=1;
Z1:=0;
while R2>=R do
begin
Vr2:=dT*(-B*R1+A*Vr1)+Vr1;
Vz2:=dT*(1-Vz1*A)+Vz1;
R2:=dT*Vr1+R1;
Z2:=dT*Vz1+Z1;
R1:=R2;
Z1:=Z2;
Vr1:=Vr2;
Vz1:=Vz2;
end;
WriteLn(A,Z2);
WriteLn(K,A,Z2);
A:=A+dA;
end;
ReadLn;
close(K);
assign(S,'C:\ZR2.txt');
rewrite(S);
Vr1:=0;
Vz1:=1;
B:=0.01;
A:=9/40;
dT:=0.01;
R2:=1;
R1:=1;
Z1:=0;
while R2>=sqrt(0.3) do
begin
Vr2:=dT*(-B*R1+A*Vr1)+Vr1;
Vz2:=dT*(1-Vz1*A)+Vz1;
R2:=dT*Vr1+R1;
Z2:=dT*Vz1+Z1;
R1:=R2;
Z1:=Z2;
Vr1:=Vr2;
Vz1:=Vz2;
WriteLn(R2,Z2);
WriteLn(S,R2,Z2);
end;
ReadLn;
close(S);
end.

Ошибся немного.Вот исправленный.